ASCE7 Ice Loads

[MWPC]

I am designing the foundation for a minor tower. The specifications included design of ice loads from ASCE7-02. When I use eqn 10-1 to calculate the area it seems excessive. It takes a length times a width (a rectangle) and then multiplies it by pi. I understand pi*D^2/4 as an area but the division by 4 is missing. I checked ASCE7-05 but the eqn is the same. I do not have a copy of ANSI/EIA/TIA222. Does it have a comparable eqn? ASCE7 already doubles the ice thickness to go from a "radius" to "diameter" type calculation. Thanks

 

[UcfSE]

It seems that ice would form over the surface area, not the cross sectional area. To get surface area, I would expect you to take length times width times 4 for a rectangular section. Pi is less than 4. Does it seem so unreasonable then?

 

[Robertmet]

BTW an 800' tower recently came down due to combined high wind and ice.This belonged to

http://www.wnep.com

in Scranton ,see photos on the website.