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ASME VIII-1 welding for internal projection nozzle on standard blind flange 1

FPPE

Mechanical
Mar 4, 2022
187
Hi,

I have a question about the calculation in accordance with ASME VIII-1 for the configuration shown below:

Immagine 2025-01-18 122643.jpg

what are the reference paragraphs for the calculation of the standard blind flange with a 4" nozzle inserted as shown in the detail? Being a standard component but modified due to the presence of a hole, it needs to be verified in accordance with the code. Could it be calculated as a slip-on, considering the 4" pipe as if it were the shell of the flange?

Thanks in advance
 
Solution
@FPPE,
I've found some old threads from this forum that might help you:

The last one seems to be very helpful
Replies continue below

Recommended for you

"Question 3: An ASME B16.5 reducing flange requiring a hub has an axial hole in the center that exceeds the size limits in UG-36(c)(3). Is it acceptable for Section VIII, Division 1 construction to use the ASME B16.5 pressure-temperature ratings for this flange without performing the reinforcement calculation per UG-39?

Reply 3: Yes"


I understand that in my case (12" blind with a 4" nozzle), I could use (referring to Table 6 of ASME B16.5) a reducing flange with the dimensions of a 12" blind, plus the hub of a 4" WN welded to above pipe. Considering that the 4" pipe has a thickness of 13.49 mm, the internal diameter of the blind would be (114.3 - 2*13.49) 87.32 mm.

In this case, no calculation would be required according to ASME VIII-1, and we can simply follow the pressure-temperature rating of B16.5.
Is my interpretation correct?
I think that your interpretation is correct.
I suggest you to ask your A.I.
Note that some provinces and jurisdiction sometimes don't accept the use of Interpretations.

As for the weld design - I think the UW-16.1(i) or (l) might be suitable for you case, pay attention to the symbols and notes.
 

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