Chrissy123
Mechanical
- Feb 17, 2019
- 29
Hi all - I'm going back to basics with my pressure vessel analysis and starting with ASME to calculate the acceptable operating pressure of a pressure vessel. My model is simple - flat head cylindrical. Length of cylinder 500mm, inside radius 254mm, cylinder shell thickness 100mm, flat head thickness 10mm, material properties, E=107GPa, poissons =0.3, yield 207 MPa. From the ASME Boiler and Pressure Vessel Code, Section VIII, Div. I, UG-27, the thickness of a cylindrical shell under internal pressure must be no less than
𝑡 = 𝑃𝑅/(𝑆𝐸 − 0.6𝑃) but this is for the thickness of the shell of the cylinder. I have found this equation for the thickness of the flat head:
.
I'm making the assumption that Corrosion is zero and welding efficiency is 1 (just for this simple calcuation), C=0.33 for a weld
d = inner diameter = (2*inside radius) = 508mm, S=allowable stress which from this forum is 2/3Yield = 138MPa,
So re-arranging the equation gives a formula for Acceptable Operating P as P=(t^2*S*E)/(d^2*C) = (10^2*138*1)/(508^2*0.33) = 0.16Mpa .... is that a reasonable ball-park figure?
thanks,
𝑡 = 𝑃𝑅/(𝑆𝐸 − 0.6𝑃) but this is for the thickness of the shell of the cylinder. I have found this equation for the thickness of the flat head:
I'm making the assumption that Corrosion is zero and welding efficiency is 1 (just for this simple calcuation), C=0.33 for a weld
d = inner diameter = (2*inside radius) = 508mm, S=allowable stress which from this forum is 2/3Yield = 138MPa,
So re-arranging the equation gives a formula for Acceptable Operating P as P=(t^2*S*E)/(d^2*C) = (10^2*138*1)/(508^2*0.33) = 0.16Mpa .... is that a reasonable ball-park figure?
thanks,