ameenbassam
Marine/Ocean
- Feb 2, 2015
- 12
Hi There,
In an article called 'An Energy Management System of a Fuel Cell/Battery Hybrid Boat', the author assumed values of charging, discharging, and optimum power of the battery as follows:
charging, discharging, and optimum power values for battery (Poptchar, Poptdis, and PBATopt ),
where charging power equals to discharging power with 30% capacity of battery and optimum power value is 20% capacity of the battery; the battery has 360 Ah and 560 V.
My question is, How the battery capacity will be converted to power ?
I know that Battery total energy = 360*560 Wh. So, i can calculate energy of 30% and 20% of it. But i need time to convert it to power.
If nominal current is 72 A. Then time for 30% of the capacity = 0.3*360/72 = 1.5 h and for 20% capacity is 1 hour. If I divide the energy of 30% capacity and 20% of the capacity over time of 1.5 hr and 1 hr, I have the same amount of power of 40320 W. What am i missing ? or it is a mistake of the article author ?
Many Thanks in advance
In an article called 'An Energy Management System of a Fuel Cell/Battery Hybrid Boat', the author assumed values of charging, discharging, and optimum power of the battery as follows:
charging, discharging, and optimum power values for battery (Poptchar, Poptdis, and PBATopt ),
where charging power equals to discharging power with 30% capacity of battery and optimum power value is 20% capacity of the battery; the battery has 360 Ah and 560 V.
My question is, How the battery capacity will be converted to power ?
I know that Battery total energy = 360*560 Wh. So, i can calculate energy of 30% and 20% of it. But i need time to convert it to power.
If nominal current is 72 A. Then time for 30% of the capacity = 0.3*360/72 = 1.5 h and for 20% capacity is 1 hour. If I divide the energy of 30% capacity and 20% of the capacity over time of 1.5 hr and 1 hr, I have the same amount of power of 40320 W. What am i missing ? or it is a mistake of the article author ?
Many Thanks in advance