To complete the answer by RichLeimbach you can get a first approximation by assuming the spring rotates under load around a point situated at radius
ro=(
R-
r)/ln(
R/
r)
where
R and
r are respectively outer and inner radius of the undeformed spring.
If
ho is the height of the spring (to be taken at mid thickness, this is called
ho in DIN 2093, see the site below under 'Other' to see standard sizes), then you can find the following formula for the relative variation of inner radius (just derived on the spot, hope it is correct):
[(
R/
r-1)/ln(
R/
r)-1]
ho2/
R2
Now, as for commercial or standard Bellevilles
R/
r is normally close to 2 and
ho/
R is a few percent (say 0.02), the term in square brackets is of the order of 0.5 and the other term of the order of 0.0004. Hence the change in inner radius is of the order of 2 per ten thousands (of course the increase in outer radius behaves similarly).
I am curious to know what kind of application you are working on, as these changes of dimensions are really small and normally negligible (though some gap should normally be provided if the inner or outer radii are closely guided). prex
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