Another way is to remember that 1 lbmole occupies 379.6 scf.
Thus, 15 MMscfd = 39,515 lbmole/day or 1,646.5 lbmole/hr. CO2 = 44.01 lb/lbmole so the flow is 72,461 lb/hr.
Pretty much the same answer. You can also use the ideal gas equation PV = nRT, P is the pressure, 1 atm. V is the volume, 15 MM ft3/day (at standard conditions of course), R is the gas constant, 0.73 atm ft3/lbmole deg F and T is the temperature, 520 deg R (at standard conditions, 60F). Solve for n, the number of moles and then multiply by the molecular weight to get the mass flow.