nickjk
Mechanical
- May 10, 2007
- 74
In a current design I am applying a axial compression force onto a shaft. During testing I was suprised at the difference between the calculated axial deformation and the measured axial deformation. Before I can move forward in correcting the design I need to have a better understanding where my calculations or measuring equipment failed. Any help would greatly be appreciated.
Formula used Delta = (F x L)/(A x E)
F=axial force applied, L=axial length of steel tube, A=effective area of tube cross section, E=modulas of elasticity for steel
To simply the test I used a simple tube shape with the following dimensions O.D. = .938 in. I.D. = .618 in. length = 2.990 in. E for steel 30,000,000 psi
A 2000 lbs axial load is applied slowly to the tube.
From my calculations the deformation should have been .00051 in.
The testing machine is showing a deformation of between .00115 and .00120 in.
The testing machine ram is 1.7500 diameter traveling thru close tolerance bushing to prevent angularity in vektors.
The transducer is mounted between the top of the ram and the coupler that connects to the hydraulic cylinder. The indicator readings are taken at the bottom of the ram.
Thank You
Nick
Formula used Delta = (F x L)/(A x E)
F=axial force applied, L=axial length of steel tube, A=effective area of tube cross section, E=modulas of elasticity for steel
To simply the test I used a simple tube shape with the following dimensions O.D. = .938 in. I.D. = .618 in. length = 2.990 in. E for steel 30,000,000 psi
A 2000 lbs axial load is applied slowly to the tube.
From my calculations the deformation should have been .00051 in.
The testing machine is showing a deformation of between .00115 and .00120 in.
The testing machine ram is 1.7500 diameter traveling thru close tolerance bushing to prevent angularity in vektors.
The transducer is mounted between the top of the ram and the coupler that connects to the hydraulic cylinder. The indicator readings are taken at the bottom of the ram.
Thank You
Nick