stuckoutthere
New member
- Mar 15, 2010
- 11
Good Evening,
I am trying to work out the litres per minute required to flush a length of 10mm O/D tubing with 1.5mm Wall Thickness. I know I need to achieve a reynolds number of 4000 to flush it.
I calculated it as below but I think it may be wrong:
1. Find out fluid kinematic viscosity at 20 degrees Celsius in centistokes for the flushing fluid you will be using.
2. Convert from centistokes to m2/s by multiplying by x10^-6
3. Find tube internal diameter in inches or metric
4. Divide bore diameter in inches by 39.370 to give you metres, If in mm then convert to metres by dividing by 1000
5. Find tube cross sectional area by multiplying pi by the bore diameter squared divided by 4
6. Find the flow rate in m^3/s by multiplying the tube cross sectional area by 4000(Reynolds number required for turbulent flow)by the fluid kinematic viscosity in m^2/s then divide it by the bore diameter.
7. Find the flow rate in L/Min by multiplying the flow rate in m^3/s by 1000 then by 60
8. This will give you required flow rate in l/min to achieve a Reynolds number of 4000 at 20 degrees Celsius(fluid temperature)
See Calculations Below: (Example)
1. Fluid Kinematic Viscosity at 20 degrees is 4.4cSt
2. 4.4 x10^-6 = 0.0000044m^2/s
3. Tube internal diameter is 0.125”
4. 0.125/39.370 = 0.003175m
5. 3.14x((0.003173^2)/4)=7.91329x10^-6m^2
6. 7.91329x10^-6((4000x0.0000044)/0.003175)=4.38658x10^-5
7. (4.38658x10^-5*1000)x60 = 2.6L/Min@20Degrees Celsius.
Is this correct or am I completely wrong. If this is wrong can someone point me in the correct direction.
Thanks
I am trying to work out the litres per minute required to flush a length of 10mm O/D tubing with 1.5mm Wall Thickness. I know I need to achieve a reynolds number of 4000 to flush it.
I calculated it as below but I think it may be wrong:
1. Find out fluid kinematic viscosity at 20 degrees Celsius in centistokes for the flushing fluid you will be using.
2. Convert from centistokes to m2/s by multiplying by x10^-6
3. Find tube internal diameter in inches or metric
4. Divide bore diameter in inches by 39.370 to give you metres, If in mm then convert to metres by dividing by 1000
5. Find tube cross sectional area by multiplying pi by the bore diameter squared divided by 4
6. Find the flow rate in m^3/s by multiplying the tube cross sectional area by 4000(Reynolds number required for turbulent flow)by the fluid kinematic viscosity in m^2/s then divide it by the bore diameter.
7. Find the flow rate in L/Min by multiplying the flow rate in m^3/s by 1000 then by 60
8. This will give you required flow rate in l/min to achieve a Reynolds number of 4000 at 20 degrees Celsius(fluid temperature)
See Calculations Below: (Example)
1. Fluid Kinematic Viscosity at 20 degrees is 4.4cSt
2. 4.4 x10^-6 = 0.0000044m^2/s
3. Tube internal diameter is 0.125”
4. 0.125/39.370 = 0.003175m
5. 3.14x((0.003173^2)/4)=7.91329x10^-6m^2
6. 7.91329x10^-6((4000x0.0000044)/0.003175)=4.38658x10^-5
7. (4.38658x10^-5*1000)x60 = 2.6L/Min@20Degrees Celsius.
Is this correct or am I completely wrong. If this is wrong can someone point me in the correct direction.
Thanks