This is going to be very elementary for most of you structural guys. In my defense, I have a mechanical degree and I work for a structural fabricator as a project manager. I haven't done any true engineering in about 5 years - so I am a bit rusty. Fair warning, I will have follow up questions to this question.
My boss has requested that I design a free-standing deck for his house. For simplistic sakes, the deck is 40' x 25'. He wants to support this deck with only using 6 columns: 1 at each corner and 1 in the center of the 25' span on each end (the 40' width runs parallel to the house). this means that my largest beam member will be the center beam spanning 40' and carrying 12'-6" of tributary loading.
Load requirements for his area are 40/10. Because I know my boss, I am bumping the live load to 50 and will calculate the dead based on material used including secondary beam points.
For secondary beams, spaced 4' on center and spanning 12'-6", I have determined that a W8x15 will sifficiently carry this load. The end reactions of these beams are 1345 lbs (each end).
For the central beam, how do I need to calculate it:
1. Base the loading on the 50 psf live load and then add in the weight of the secondary beams every 4' feet on center?
2. Just use double the reaction load of the w8x15 every 4' on center? Double since there will be W8x15 off to each side every 4' on center.
Each way gives a wildly different answer. Like a W18x40 vs a W24x104.
My boss has requested that I design a free-standing deck for his house. For simplistic sakes, the deck is 40' x 25'. He wants to support this deck with only using 6 columns: 1 at each corner and 1 in the center of the 25' span on each end (the 40' width runs parallel to the house). this means that my largest beam member will be the center beam spanning 40' and carrying 12'-6" of tributary loading.
Load requirements for his area are 40/10. Because I know my boss, I am bumping the live load to 50 and will calculate the dead based on material used including secondary beam points.
For secondary beams, spaced 4' on center and spanning 12'-6", I have determined that a W8x15 will sifficiently carry this load. The end reactions of these beams are 1345 lbs (each end).
For the central beam, how do I need to calculate it:
1. Base the loading on the 50 psf live load and then add in the weight of the secondary beams every 4' feet on center?
2. Just use double the reaction load of the w8x15 every 4' on center? Double since there will be W8x15 off to each side every 4' on center.
Each way gives a wildly different answer. Like a W18x40 vs a W24x104.