Volantis
Mechanical
- May 15, 2020
- 5
Hi All,
Recently moving from the O&G industry into mining, so I have never done any calcs on conveyors / idlers.
I require some help with calculating the load on a centre roll of a suspended, 3 roll idler set. Doing some research, I find that using catenary action on a cable might be the best approach to doing this, but I have never attempted one before so would like some confirmation and guidance on doing so within this particular application.
Below are some assumptions and numbers that I will use, let me know if there are any other unknown variables that I require.
Assumptions:
70% of total load on the centre roll
Friction = 0.9
Idlers have 45 deg trough angle
Some numbers I have:
belt running at fully loaded case: Q = 15,000 tph
Belt speed: v = 5.5 m/s
Belt tension: T = 520kN
Belt Mass: M = 80 kg/m
Belt width: W = 1800 mm
Material density = 1800 kg/m3
Distances between Suspended (Idler1) and inline (Idler2):
Vertical: Z = 0.382 m
Horizontal: Y = 3.798 m
If someone could help me out / point me in the right direction, that would be greatly appreciated.
Thank yo
Recently moving from the O&G industry into mining, so I have never done any calcs on conveyors / idlers.
I require some help with calculating the load on a centre roll of a suspended, 3 roll idler set. Doing some research, I find that using catenary action on a cable might be the best approach to doing this, but I have never attempted one before so would like some confirmation and guidance on doing so within this particular application.
Below are some assumptions and numbers that I will use, let me know if there are any other unknown variables that I require.
Assumptions:
70% of total load on the centre roll
Friction = 0.9
Idlers have 45 deg trough angle
Some numbers I have:
belt running at fully loaded case: Q = 15,000 tph
Belt speed: v = 5.5 m/s
Belt tension: T = 520kN
Belt Mass: M = 80 kg/m
Belt width: W = 1800 mm
Material density = 1800 kg/m3
Distances between Suspended (Idler1) and inline (Idler2):
Vertical: Z = 0.382 m
Horizontal: Y = 3.798 m
If someone could help me out / point me in the right direction, that would be greatly appreciated.
Thank yo