Spurs
Mechanical
- Nov 7, 2002
- 297
I am having problems with a calculation and am looking for guidance from this forum.
I am looking for an accurate method to calculate the tight mesh center distance of a crossed axis helical gear mesh with heavily modified tooth thicknesses. The calculation method that I have found in most published literature is accurate only for the case where the sum of the normal circ. tooth thicknesses is equal to the normal circ. pitch. When I create designs whith shifted profiles I am finding that the calculation methods that I am aware of become less accurate.
This calculation method must be published somewhere as this is also the basis for all helical gear hobbing principles where a hob must be plunged to a center distance with the workpiece with zero backlash in order to create a perfect tooth thickness on the workpiece.
Below is a calculation example:
Driving Member Worm - 1 start
Driven Gear - 14 Tooth Helical Gear
Normal Module of both parts 3.5
Helix Angle on Gear - 23 Deg
Lead Angle on Worm 23 Deg
Shaft Angle 90 deg.
Normal Pressure Angle - both parts 20 deg
Normal Circ Tooth Thickness of worm 7.770 mm
Normal Circ Tooth Thickness of gear 5.500 mm
For reference info - although it isnt needed
OD of worm 20.950 mm
OD of gear 60.000 mm
Root dia of worm 7.150 mm
Root dia of gear 44.100 mm
By conventional calculation methods, the tight mesh center distance is calculated as 33.8168 mm - I get this result when I calculate by hand, and when I use a leading commercial software package.
If you model the parts in CAD and look at tight mesh center distance - the distance is 34.200
My actual experience on a double flank tester seems to match the CAD
I am looking for any published info that would seem to provide the accurate solution. As I said earlier, I suspect that the hobbing industry has published info related to this since the same calculation must be used.
Any help would be appreciated - if someone has a more general solution that works at any shaft angle (even non 90 deg) it would be very much appreciated.
I am looking for an accurate method to calculate the tight mesh center distance of a crossed axis helical gear mesh with heavily modified tooth thicknesses. The calculation method that I have found in most published literature is accurate only for the case where the sum of the normal circ. tooth thicknesses is equal to the normal circ. pitch. When I create designs whith shifted profiles I am finding that the calculation methods that I am aware of become less accurate.
This calculation method must be published somewhere as this is also the basis for all helical gear hobbing principles where a hob must be plunged to a center distance with the workpiece with zero backlash in order to create a perfect tooth thickness on the workpiece.
Below is a calculation example:
Driving Member Worm - 1 start
Driven Gear - 14 Tooth Helical Gear
Normal Module of both parts 3.5
Helix Angle on Gear - 23 Deg
Lead Angle on Worm 23 Deg
Shaft Angle 90 deg.
Normal Pressure Angle - both parts 20 deg
Normal Circ Tooth Thickness of worm 7.770 mm
Normal Circ Tooth Thickness of gear 5.500 mm
For reference info - although it isnt needed
OD of worm 20.950 mm
OD of gear 60.000 mm
Root dia of worm 7.150 mm
Root dia of gear 44.100 mm
By conventional calculation methods, the tight mesh center distance is calculated as 33.8168 mm - I get this result when I calculate by hand, and when I use a leading commercial software package.
If you model the parts in CAD and look at tight mesh center distance - the distance is 34.200
My actual experience on a double flank tester seems to match the CAD
I am looking for any published info that would seem to provide the accurate solution. As I said earlier, I suspect that the hobbing industry has published info related to this since the same calculation must be used.
Any help would be appreciated - if someone has a more general solution that works at any shaft angle (even non 90 deg) it would be very much appreciated.