dtn6770
Mechanical
- Jul 10, 2006
- 200
I hate to resurrect a topic that’s been utterly beaten to death…but I will. Actually, I more so hate being "that guy” who brings the subject up AGAIN.
It’s the dreaded UW-11(a)(5)(b) paragraph relating to the joint efficiency. Here’s a very specific situation; Non-lethal, non-steam service, NPS 12 XH seamless shell section (SA-106-B) attached to a seamless formed, 0.500 in nominal, 2:1 ellipsoidal head (SA-516-70) with 2 inch straight flange. RT-2 is the claim. The circumferential joint will be of Type 1 and will be spot radiographed.
What joint efficiencies should be used to calculate the longitudinal stress calculations? My interpretation pushes me towards E = 0.85 but I suspect that a lot of folks would contest that for E = 1.0.
My rational is as follows.
UW-11(a)(5) applies to the full radiography requirements of Category A and D butt welds whereas the circumferential joint in question is a Category B butt weld.
UW-11(a)(5)(a) criteria is met because the Category B weld in question will be of Type 1.
UW-11(a)(5)(b) criteria is met because the Category B weld in question connects seamless vessel sections or heads and will be spot radiographed.
UW-12(d) throws out joint efficiencies (E) for calculations involving circumferential stress (longitudinal seams) NOT for longitudinal stress calculations (circumferential seams).
FIG. L-1.4-1 leads me to E = 0.85 for Category B, Type 1 butt welds because of the spot radiography.
FIG. L-1.4-2 implies E = 1.0 for a seamless head when UW-11(a)(5)(b) is met but may only apply to seamless hemispherical heads joined to main shell (Cat. A welds).
FIG. L-1.4-4 leads me to E = 0.85 because the joint is a Type 1 and will be spot radiographed.
Example L-1.5.2(b) supports the use of an E not equal to 1.0 for a Category B, Type 2, spot radiographed joint meeting UW-11(a)(5)(b).
Example L-1.5.5(b) supports the use of an E not equal to 1.0 for a Category B, Type 2, spot radiographed joint meeting UW-11(a)(5)(b).
Example L-1.5.5(f) supports the use of an E not equal to 1.0. However for a Category B, Type 2, spot radiographed joint meeting UW-11(a)(5)(b) I would expect E = 0.80 instead of the given solution of E = 0.65 which implies no radiography…a possible mistake in the solution?!
Lastly but not imply that Code software packages are always correct...APV defaults to the same longitudinal stress E (0.85) for RT-2.
It’s the dreaded UW-11(a)(5)(b) paragraph relating to the joint efficiency. Here’s a very specific situation; Non-lethal, non-steam service, NPS 12 XH seamless shell section (SA-106-B) attached to a seamless formed, 0.500 in nominal, 2:1 ellipsoidal head (SA-516-70) with 2 inch straight flange. RT-2 is the claim. The circumferential joint will be of Type 1 and will be spot radiographed.
What joint efficiencies should be used to calculate the longitudinal stress calculations? My interpretation pushes me towards E = 0.85 but I suspect that a lot of folks would contest that for E = 1.0.
My rational is as follows.
UW-11(a)(5) applies to the full radiography requirements of Category A and D butt welds whereas the circumferential joint in question is a Category B butt weld.
UW-11(a)(5)(a) criteria is met because the Category B weld in question will be of Type 1.
UW-11(a)(5)(b) criteria is met because the Category B weld in question connects seamless vessel sections or heads and will be spot radiographed.
UW-12(d) throws out joint efficiencies (E) for calculations involving circumferential stress (longitudinal seams) NOT for longitudinal stress calculations (circumferential seams).
FIG. L-1.4-1 leads me to E = 0.85 for Category B, Type 1 butt welds because of the spot radiography.
FIG. L-1.4-2 implies E = 1.0 for a seamless head when UW-11(a)(5)(b) is met but may only apply to seamless hemispherical heads joined to main shell (Cat. A welds).
FIG. L-1.4-4 leads me to E = 0.85 because the joint is a Type 1 and will be spot radiographed.
Example L-1.5.2(b) supports the use of an E not equal to 1.0 for a Category B, Type 2, spot radiographed joint meeting UW-11(a)(5)(b).
Example L-1.5.5(b) supports the use of an E not equal to 1.0 for a Category B, Type 2, spot radiographed joint meeting UW-11(a)(5)(b).
Example L-1.5.5(f) supports the use of an E not equal to 1.0. However for a Category B, Type 2, spot radiographed joint meeting UW-11(a)(5)(b) I would expect E = 0.80 instead of the given solution of E = 0.65 which implies no radiography…a possible mistake in the solution?!
Lastly but not imply that Code software packages are always correct...APV defaults to the same longitudinal stress E (0.85) for RT-2.