Continue to Site

Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

  • Congratulations GregLocock on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

CENTRIFUGAL FORCE - AGAIN 1

Status
Not open for further replies.

CGOFM

Industrial
Apr 28, 2008
3
Hello to all...
I have chased down a few threads to see comments on calculating centrifugal force and end up with so many different answers by experts...

Can anyone verify my calculation...gravity is not part of this at the moment:

r (radius) = 0.1524 m (6 inches)
m (mass/weight) = 0.227272727 kg (0.5 lbs)
rpm = 250

[w = 2*3.14*250/60 = 26.18 rad/s]

CF = m*w*w*r = 23.7395 Newtons or 5.3368 lbs

 
Replies continue below

Recommended for you

Yoar are right to at least one sf

Cheers

Greg Locock

SIG:please see FAQ731-376 for tips on how to make the best use of Eng-Tips.
 
... what sort of mechanism though? Is "r" a crank radius?

- Steve
 
Hello Greg...
Thanks for your response.
As a consequence, this also helped me build a calculator in excel, where i can change any of the 3 variables, giving me results in metric and english.
Greatly appreciated,
Christoph
 
Hi Steve...
Yes it's a crank radius.
I'm building a double piston of my own design.
Should be interesting....
What is your automotive specialty?
Thanks...Christoph
 
As Steve hints, I assumed that the r term was the effective raius of the mass... not its overall radius.

Cheers

Greg Locock

SIG:please see FAQ731-376 for tips on how to make the best use of Eng-Tips.
 
Well... That is the radial force required to rotate a point mass at that radius. But it's unlikely that your system is that simple.

(My specialty? Check out "My Info". It's fairly up-to-date)

- Steve
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor