Edelma_1
Electrical
- Apr 16, 2024
- 31
I came across a formula for circuit protective conductors in bS76761 18th edition page 196 which states S=sqrt(1[sup]2[/sup]*t)/k
where S is the csa (mm[sup]2[/sup]) of the conductor
I is the fault current
t is the time in seconds for disconnection
k is the factor taking account of coefficient, temperature and the likes
what I don`t understand is which fault current is being talked about here, is it the earth fault?
where S is the csa (mm[sup]2[/sup]) of the conductor
I is the fault current
t is the time in seconds for disconnection
k is the factor taking account of coefficient, temperature and the likes
what I don`t understand is which fault current is being talked about here, is it the earth fault?