rrossey
Mechanical
- Dec 13, 2010
- 10
I am constructing a compound cylinder to withstand an internal pressure of 6,000 psi.
The construction is from two pipes
Inner pipe material seamless Stainless Steel 316
ID = 4.00”
OD = 4.25”
Wall thickness = 0.125”
Outer pipe material seamless Steel 1018
ID = 4.375”
OD = 6.625”
Wall thickness = 1.125”
Both ends of the 48” long cylinder to be closed by 1.25” thick flanges with proper seals.
There is a gap of 1/16” between the inner and outer pipe. I propose to fill this gap with a high strength epoxy.
As per the Barlows formula, the outer pipe bursting pressure works out to be 24,000 psi. This gives a safety factor of 4 for a working pressure of 6,000 psi.
I request your suggestions regarding the construction and any design flaws.
Thanks
The construction is from two pipes
Inner pipe material seamless Stainless Steel 316
ID = 4.00”
OD = 4.25”
Wall thickness = 0.125”
Outer pipe material seamless Steel 1018
ID = 4.375”
OD = 6.625”
Wall thickness = 1.125”
Both ends of the 48” long cylinder to be closed by 1.25” thick flanges with proper seals.
There is a gap of 1/16” between the inner and outer pipe. I propose to fill this gap with a high strength epoxy.
As per the Barlows formula, the outer pipe bursting pressure works out to be 24,000 psi. This gives a safety factor of 4 for a working pressure of 6,000 psi.
I request your suggestions regarding the construction and any design flaws.
Thanks