I talked to other engineers in my country. They all are unaware of what Ron is saying about strain incompatibility. So I spent many days reading many references and computing stuff in order to prove to them there is load reduction using epoxy filling (especially my structural engineer who forgot about the concept).
I read about the above graph:
"Elastic Behavior. At low stresses, up to about fc'/2, the concrete is seen to behave nearly elastically, i.e. stresses and strains are quite proportional; the straight line d represents this range of behavior with little error for both rates of loading. For the given concrete, the range extends to a strain of about 0.0005. The steel, on the other hand, is seen to be elsatic nearly to its yield point of 60 ksi, or to the much greater strain of about 0.002... Because the compression strain in the concrete, at any given load, is equal to the compression strain in the steel.... <snip>"
Now to compute for the load reduction carried by the epoxy filling. I'll use strain of 0.0005 or load in the elastic range.
from steel strain=0.0005, Modulus 29,000 ksi
stress = strain*modulus = 14500 psi or 99973.98 pascal
from concrete strain 0.0005, Modulus 3604.996 ksi
stress = strain*modulus = 1802.498 psi or 12427.79 pascal
from epoxy strain 0.0005, Modulus 450 ksi
stress = strain*modulus = 225 psi or 1551.32 pascal
Column is 0.5x0.5m, the 0.2x0.5 section was replaced with epoxy, remaining 0.3x0.5 section with concrete. In other words, 33% of section replaced by epoxy.
steel area of 12 20mm bars (for concrete section) = 0.003769 mm^2
steel aread of 8 20mm bars (for epoxy section) = 0.002513 mm^2
For load carried by concrete section (0.3x0.5 of column) with 12 bars of 20m steel
P = Fc(Ag-As)+Fs(As) = 12427.29(0.146231) + 99973.98 (0.003769)
=2194.13 KN
For load carried by the epoxy section (0.2x0.5 of column) with 8 bars of 20mm steel.
P = Fc(Ag-As)+Fs(As) = 1551.32 (0.097487) + 99973.98 (0.002513)
= 402.4681 Kn
For load carried by entirely concrete(0.5x0.5 of column) with 20 bars of 20mm steel
P = Fc(Ag-As)+Fs(As) = 12427.79(0.243718) + 99973.98(0.006282)
= 3656.913 Kn
Loss of axial load due of the epoxy is
P(all concrete) - (P(concrete)+P(epoxy)) = 3656.913 - (2194.13+402.4681) = 1060.3149 KN
For P(nominal), fc of concrete is 28,000 Pascal and steel is 414,000 Pascal.
P(nominal) = 0.85 Fc (Ag-As) + Fs(As)
=0.85 (28000)(0.243718) + 414000 (00.6282)
=8401.236 KN
P(factored) = 0.65 * 0.8 * 8401.236 KN = 4368.643
Questions: the reduction factor of 0.65 and 0.8 is only used when the fc and fs used is the designed compressive strengths (maximum of concrete 28mpa and steel 414 mpa respectively, correct? For partial, it's P=Fc(Ag-As)+Fs(As)? I saw this in the book example when solving for the load carried by the concrete and steel at 0.0005 strain or elastic load.
Is my calculations so far correct? I need to present this to my structural engineer to prove there is loss of load carried by epoxy. He thought strain is not important and it is the epoxy compressive strength that counts only.
Next I'll show him possible moment magnification factor effect (or 2nd order effects during cyclic loading) of the epoxy material due to the bars taking majority of the load. I'm doing this because I need him to authorize to replace the epoxy. Without him. I can't do anything so hope you can comment on the calculations above. I don't want to confuse him (and dozen of other engineers who are not aware of this in my country) further by sharing wrong calculations whose concept and formula he already forgot back in his school days two decades ago so need your comments. Remember almost all structures in my country are repaired with epoxy injection and the engineers assume they carry same load as concrete and ignore strain incompatibility and load reductions so this is a national emergency and I may share this in structural newsletter to bring attention to this problem which many in the industry is unaware. Many thanks.