Hokie, I've been concerned about the greater epoxy creep than concrete (details below). I'm still looking for the repair company that can do the job while trying to think how to introduce all this strain compatibility thing to my structural engineer and contractor who still literally ignore all this. Most use ETABS and STaad nowadays and almost none do it manually so they miss this epoxy thing (which they don't see at ETABs).
BA, You mean epoxy elastic strain reaches up to 0.005 while concrete crushes at 0.0035? But if you push concrete to 0.001 strain, it's axial load is much greater at 0.001x3600,000 = 3600 psi versus the epoxy 0.005x450,000 = 2250 psi. But right now. Even Sika doesn't produce stress strain curve and the spec of 400 ksi to 600 ksi come from all the epoxy manufacturer. Maybe calculated from the chemical properties of epoxy.
But there is one problem about creep. At sustained loading of strain 0.005, the capacity or curve may change to lower psi. Earlier. I mentioned that "I also learnt that for fast loading vs slow loading, the steel carries more load in slow loading because the fc is smaller in value." in which you answered "I don't know about that. I am not arguing, I simply don't know.". The following makes it clear. This epoxy thing can make one remember lessons learnt over 50 years ago. Again refer to the above figure. Quoting briefly from the book "Design of Concrete Structurs" where I learnt all this (this concept is important in this epoxy analysis):
"Example 1.2 One may want to calculate the magnitude of the axial that will produce a strain of unit shortening strain(c)=strain(s)=0.001 in the column of Example 1.1. At this strain the steel is seen to be still elastic, so that the steel stress fs=strain(Es)=0.001x29,000,000= 29,000 psi. The concrete is in the inelastic range, so that its stress cannot be directly calculated, but it can be read from the stress-strain curve for the given value of strain.
1. If the member has been loaded at a fast rate, curve b holds at the instant when the entire load is applied. The stress for strain = 0.001 can be read as fc=3200 psi. Consequently, the total load can be obtained from
P=fcAc + Fs(Ast)
which applies in the inelastic as well as in the elastic range. Hence, P=3200(320-6) + 29,000 x 6 = 1,005,000 + 174,000 = 1,179,000 lb. Of this total load, the steel is seen to carry 174,000 lb, or 14.7 percent.
2. For slowly applied or sustained loading, curve c represents the behavior of the concrete. Its stress at a strain of 0.001 can be read as fc=2400 psi. Then P=2400x 314 + 29,000 x 6 = 754,000 + 174,000 = 928,000 lb. Of this total load, the steel is seen to carry 18.8 percent.
Comparisons of the results for fast and slow loading shows the following. Owing to creept of concrete, a given shortening of the column is produced by a smaller load when slowly applied or sustained over some length of time than when quickly applied. More important, the farther the stress is beyond the proportional limit of the concrete, and the more slowly the load is applied or the longer it is sustained, the smaller the share of the total load carried by the concrete and the larger the share carried by the steel. In the sample column, the steel was seen to carry 13.3 percent of the load in the elastic range, 14.7 percent for a strain of 0.001 under fast loading, and 18.8 percent at the same strain under slow or sustained loading.