sasa000
Chemical
- Jun 7, 2022
- 8
Using Woods 'Rules of Thumb in Engineering Practice' (2007) Appendix D cost estimation approach (easily available to download online as pdf - won't link as probably not kosher).
Section D.2 / Page 377 suggests there are two ways to estimate the Bare Module (BM) cost correcting for L+M*, however I seem to be calculating wildly different (L+M* - FOB) costs for each (ie. the BM installation cost not including actual equipment)
These are the two approaches, ignoring for now other factors like pressure correction factors:
i) Reduce the reference L+M* factor (typically at CS) by the value/plot suggested after correcting for Material of Construction => BM = FOBcs x Alloy Factor x L+M*ref x (L+M* correction factor)
ii) Calculate the BM cost as CS (FOBcs x L+M*ref), then add on the differential BOM cost for the MOC eg for stainless steel. BM = (FOBcs x L+M*ref) +(FOBss - FOBcs)
If we're just looking at the L+M part of the costs, these two approaches give wildly different answers:
Taking for example a radial blade centrifugal fan as an example (Appendix D Section 2.1), say at the reference 10Nm3/s condition (and ignoring CEPCI correction for now):
FOBref = $15,850
L+M*ref = 1.4-1.7 (assume 1.4)
Alloy Factor (CS) = 1.00
SS = 2.5 -> gives correction factor of around 0.65 per Figure D.1
Method 1: BM cost = $15,850 x 2.5 x (1.4 x 0.65) = $36,058
The L+M* part of said cost therefore = BM cost - FOB cost = $36,058 - 15,850 x 2.5 = -$3,567
So therefore the L+M* Material correction actually makes the BM cost cheaper vs reference case (L+M -1).
Method 2: BM cost = $15,850 x 1.4 + $15,850 x (2.5 - 1) = $22190 + $23775 = $45,965
The L+M* cost is therefore just the CS L+M* cost (1.4 - 1) x $15,850 = $6,340
Woods seems like a fairly respected methodology, but the two methods suggested give wildly different answers! As far as I can tell I'm using the correct approach (though the text could do with a few more developed examples). I wonder if method 1 is supposed to be written to state that the L+M* correction should only be applied to the incremental material corrected FOB cost, but the text is not written to define it that way and that still wouldn't solve method 2 giving a negative correction (ie. therefore stating that a higher material grade installation cost would be cheaper than CS).
Section D.2 / Page 377 suggests there are two ways to estimate the Bare Module (BM) cost correcting for L+M*, however I seem to be calculating wildly different (L+M* - FOB) costs for each (ie. the BM installation cost not including actual equipment)
These are the two approaches, ignoring for now other factors like pressure correction factors:
i) Reduce the reference L+M* factor (typically at CS) by the value/plot suggested after correcting for Material of Construction => BM = FOBcs x Alloy Factor x L+M*ref x (L+M* correction factor)
ii) Calculate the BM cost as CS (FOBcs x L+M*ref), then add on the differential BOM cost for the MOC eg for stainless steel. BM = (FOBcs x L+M*ref) +(FOBss - FOBcs)
If we're just looking at the L+M part of the costs, these two approaches give wildly different answers:
Taking for example a radial blade centrifugal fan as an example (Appendix D Section 2.1), say at the reference 10Nm3/s condition (and ignoring CEPCI correction for now):
FOBref = $15,850
L+M*ref = 1.4-1.7 (assume 1.4)
Alloy Factor (CS) = 1.00
SS = 2.5 -> gives correction factor of around 0.65 per Figure D.1
Method 1: BM cost = $15,850 x 2.5 x (1.4 x 0.65) = $36,058
The L+M* part of said cost therefore = BM cost - FOB cost = $36,058 - 15,850 x 2.5 = -$3,567
So therefore the L+M* Material correction actually makes the BM cost cheaper vs reference case (L+M -1).
Method 2: BM cost = $15,850 x 1.4 + $15,850 x (2.5 - 1) = $22190 + $23775 = $45,965
The L+M* cost is therefore just the CS L+M* cost (1.4 - 1) x $15,850 = $6,340
Woods seems like a fairly respected methodology, but the two methods suggested give wildly different answers! As far as I can tell I'm using the correct approach (though the text could do with a few more developed examples). I wonder if method 1 is supposed to be written to state that the L+M* correction should only be applied to the incremental material corrected FOB cost, but the text is not written to define it that way and that still wouldn't solve method 2 giving a negative correction (ie. therefore stating that a higher material grade installation cost would be cheaper than CS).