converting torque into force

[dummiboi]

hi guys,

i'm new to these forums but you guys seem to really know your stuff.

anyways, i have this problem. i have this nut that is supposed to lock down this bearing. and the bearing is supposed to be locked down with say 15 lbs of force. how do i calculate how much torque is needed to correspond to this 15 lbs of force?

do you guys know anything about the factors involved or any equations i could use?

thanks much,
-j

 

[byrdj]

Force = Torque divided by (Thread pitch + Thread Friction factor + nut friction factor)

Thus to calculate you need to know;

Threaded shaft diameter
nut contact diameter
nut contacting surfaces coeffictiant of frition (function of material and lubricant)
thread contacting surfaces coeffictiant of frition (function of material, lubricant and thread type angle)
Thread pitch (threads per inch)

red flag express

 

[CoryPad]

faq725-536

Regards,

Cory

Please see FAQ731-376 for tips on how to make the best use of Eng-Tips Fora.

 

[sms]

Please see FAQ731-376 for tips on how to make the best use of Eng-Tips Fora.

-The future's so bright I gotta wear shades!

 

[dummiboi]

awesome.

but do you guys know where the .16 and the .58 come from? i'm assuming the .16 is pi/2 but i wanna make sure.

thanks again,
-j

 

[CoryPad]

The factor 0.16 comes from 1/(2[·][π]), while the 0.58 factor comes from 1/[2[·]cos(30)]. If you need to understand the equations in more detail, you should read the source document (VDI 2230).

Regards,

Cory

Please see FAQ731-376 for tips on how to make the best use of Eng-Tips Fora.