cooling towers losses 4

[gbl62]

Could someone give me a hint on the practical calculation of evaporation and drift losses in an induced draft counterflow tower?
Thanks

 

[quark]

If you have 1 kg of water/sec circulating and the tower range is 5⁰C, then heat to be removed is about 1*4.2*5 = 21kJ/sec. The latent heat of water is 2430kJ/kg. So amount of water to be evaporated is 21/2430 = 0.0086kgs. This becomes 0.86%.

Roughly 0.9% is considered for all practical calculations, nevertheless you can use the above method to find out evaporation losses.

With best quality drift eliminators, you consider 0.1% losses.

The blowdown can be calculated as ER/(C-1), where ER is rate of evaporation and C is cycles of concentration.

The link below gives you good concept about cooling towers.

http://www.cheresources.com/ctowerszz.shtml

 

[mbeychok]

gbl62:

This FAQ has exactly what you are looking for:

faq798-1152 <== click here

Milton Beychok
(Visit me at www.air-dispersion.com)
.