Cooling Water Flow

[eng2hot]

I'm trying to determine the amount of water flow I will need to cool a heated platen (350 to 70 deg) in 1 hour. The platen is made of stainless steel and is 48" by 48" by 4" thick. Water flows inside the platens.

Any help on equations that apply will be appreciated.

 

[XELR8]

Here is your answer:

Mass = Vol*Density = 48x48x4/144 (40.8 lbs/ft^2*in) = 2611 lbs

Energy used to heat steel
kW = m*Cp*dT/3412*Hrs = 2611 lbs(0.12 Btu/lb/F)(350-70)/(3412*1hr) = 25.7 kWhr = 87688 Btu/hr

Energy gained by water to cool steel to say 150F
m = q/(Cp*dT) = 87688 Btu/hr / (1 Btu/lb/F)(150-70)
m = 1096 lbs/hr = 18.27 lbs/min / 8.31 lbs/gal = 2.2 gal/min.
I am not sure of all your system variables but this should be close enough.

 

[eng2hot]

Thank you Dracula