nscherneck
Electrical
- Mar 7, 2006
- 6
Hey everyone,
I'm designing a fire alarm system in which i'll be using a parallel circuit with a few seperate legs. See attached.
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I prefer to do point-to-point voltage drop calculations with the following formula...
V - (R)(A)(W)
Where
V = Starting voltage
R = Resistance of wire (per foot)
W = Length of wire (both conductors)
A = Cummulative current
So for instance, lets say all devices are drawing 50mA each. Device one is 30' from the source, device two is 45' from device one, and device three is 45' from device two. We typically use a 14AWG wire which has .00307 ohms of resistance per foot (per Ugly's). Starting voltage is 24vdc. Here's how I calculate the voltage drop...
"Leg 1" voltage drop calculation
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Device 1... 24 - (.00307)(.150)(60) = 23.97
Device 2... 23.97 - (.00307)(.100)(90) = 23.94
Device 2... 23.94 - (.00307)(.050)(90) = 23.92
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For my circuit that has seperate legs (see attached), i want to calculate each leg point-to-point. I just calculated "Leg 1" above and can easily calculate "Leg 2" using the same method. My question is how do I calculate "Leg Main"? Would I use the cummulativ current for "Leg 1" and "Leg 2" like so?...
"Leg Main" voltage drop calculation
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Device 1 (Leg 1)... 24 - (.00307)(.500)(60) = 23.90
Device 2 (Leg 2)... 23.90 - (.00307)(.350)(120) = 23.77
Device 3... 23.77 - (.00307)(.200)(240) = 23.62
Device 4... 23.62 - (.00307)(.150)(90) = 23.58
Device 5... 23.58 - (.00307)(.100)(90) = 23.55
Device 5... 23.55 - (.00307)(.050)(90) = 23.54
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Nathan Scherneck, NICET II (fire alarm)
National Fire Protection
Honolulu, HI
I'm designing a fire alarm system in which i'll be using a parallel circuit with a few seperate legs. See attached.
------------------------------------------------
I prefer to do point-to-point voltage drop calculations with the following formula...
V - (R)(A)(W)
Where
V = Starting voltage
R = Resistance of wire (per foot)
W = Length of wire (both conductors)
A = Cummulative current
So for instance, lets say all devices are drawing 50mA each. Device one is 30' from the source, device two is 45' from device one, and device three is 45' from device two. We typically use a 14AWG wire which has .00307 ohms of resistance per foot (per Ugly's). Starting voltage is 24vdc. Here's how I calculate the voltage drop...
"Leg 1" voltage drop calculation
-------
Device 1... 24 - (.00307)(.150)(60) = 23.97
Device 2... 23.97 - (.00307)(.100)(90) = 23.94
Device 2... 23.94 - (.00307)(.050)(90) = 23.92
-------
------------------------------------------------
For my circuit that has seperate legs (see attached), i want to calculate each leg point-to-point. I just calculated "Leg 1" above and can easily calculate "Leg 2" using the same method. My question is how do I calculate "Leg Main"? Would I use the cummulativ current for "Leg 1" and "Leg 2" like so?...
"Leg Main" voltage drop calculation
-------
Device 1 (Leg 1)... 24 - (.00307)(.500)(60) = 23.90
Device 2 (Leg 2)... 23.90 - (.00307)(.350)(120) = 23.77
Device 3... 23.77 - (.00307)(.200)(240) = 23.62
Device 4... 23.62 - (.00307)(.150)(90) = 23.58
Device 5... 23.58 - (.00307)(.100)(90) = 23.55
Device 5... 23.55 - (.00307)(.050)(90) = 23.54
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Nathan Scherneck, NICET II (fire alarm)
National Fire Protection
Honolulu, HI