Continue to Site

Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

  • Congratulations IDS on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

Dead Leg Freezing Versus Thermosyphon

Status
Not open for further replies.

ChemEngSquirrel

Chemical
Jun 10, 2010
72
I have a 12" water pipe flowing at 50deg C with a long 2" vertical dead leg in the 12 o'clock position. Can i rely on the thermosyphon effect (hot water rising into dead leg due to high density) to justify not heat tracing the 2" stagnant line.

The line can be exposed to min ambient temps of -15 deg C.

Thanks.
 
Replies continue below

Recommended for you

I don't think, because the water has to rise and fall in the same pipe. Warm water will rise up the center and fall at the pipe wall and the streams will be exchanging heat at the same time. It will work to some limited extent, but I wouldn't count on it.
 
I would say that 2" is too small and that it should be heat traced
 
A "long" 2" - 2 INCH?? If it is 2" I would just insulate it and rely on heat conduction through the pipe wall to prevent freezing. The water might not be a 50 C, but shouldn't freeze.

If it is 2 FEET, then no, a 2" pipe won't conduct enough heat to prevent this and you need to trace heat this line.

My motto: Learn something new every day

Also: There's usually a good reason why everyone does it that way
 
Sorry, I read this as 2" long dead leg.... I should re-read before posting, but the point applies - what is "long"?

My motto: Learn something new every day

Also: There's usually a good reason why everyone does it that way
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor