Continue to Site

Eng-Tips is the largest engineering community on the Internet

Intelligent Work Forums for Engineering Professionals

  • Congratulations waross on being selected by the Eng-Tips community for having the most helpful posts in the forums last week. Way to Go!

Difference between Static Head (Elevation Head) & Hydrostatic Pressure Head

Status
Not open for further replies.

iamjustanewbie

Mechanical
Jun 15, 2015
14
Hi

I am confused with the Difference between Static Head (Elevation Head) & Hydrostatic Pressure Head.

Can anybody help me with this?

Thanks in advance.
 
Replies continue below

Recommended for you

Is there a difference?

Sounds like the same thing just stated slightly differently.

Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
 
I think there is a difference between them. By formula,

TDH = Pressure Head + Velocity Head + Elevation Head - Head Loss(friction head loss)
TDH = ((P2-P1)/specific weight) + ((V2-V1)/2g) + (Z2-Z1) - Head Loss

And also, formula for Hydrostatic Pressure Head is P = (specific weight) * H

So, Hydrostatic Pressure Head is the same as Pressure Head in the above formula.

Am I correct?

 
Be careful with words. TDH is something completely different. your words used in the first post were "Static Head (Elevation Head) & Hydrostatic Pressure Head"

I think I see where you are coming from.

Definition to use perhaps - Static head(elevation) is that head produced by raising your fluid from one elevation to another, lets say ground level (0m) to a tank on top of a building (say 30m)

Hydrostatic Pressure Head is an incorrect mixture of terms. I think what you mean is Hydrostatic pressure converted to head. Hydrostatic pressure is simply the pressure exhibited by a column of water which is not moving - hence the "static" bit.

Clearly these are different things.

Your use of the term Pressure head in the formula is also stagne. Normally TDH is simply the inlet pressure or head PLUS the head imparted by the pump. That's it, nothing more.

I actually don't know what that is you are calculating there.

You seem to be complicating this a lot. Be careful of the units you use as well, it's easy to get them mixed up.


Remember - More details = better answers
Also: If you get a response it's polite to respond to it.
 
You should probably look this up in your dynamics of fluids textbook.
 
Status
Not open for further replies.

Part and Inventory Search

Sponsor