Walterke
Industrial
- Jun 22, 2011
- 451
I've been asked to put a safety rail on a structure that has to be able to support 3 people falling off
The rail would be 4m long and the people are attached to 2m long safety lines.
So worst case scenario is all 3 of them fall simultaneously in the middle of the rail and fall down 2 meters before their lifeline pulls the rail.
If anyone has any ideas of how to calculate the required strength of the rail, your help would be appreciated.
(rail would be S355 steel and is allowed to deform but not break)
Google only gives me formulas where you have to 'assume' a certain amount of deflection to calculate the impact force, but that doesn't seem to be what I'm looking for.
I've tried using m.g.h=kx²/2 where:
k=48EI/L³
x=deflection of the rail
but kinda get stuck.
NX 7.5.5.4 with Teamcenter 8 on win7 64
Intel Xeon @3.2GHz
8GB RAM
Nvidia Quadro 2000
The rail would be 4m long and the people are attached to 2m long safety lines.
So worst case scenario is all 3 of them fall simultaneously in the middle of the rail and fall down 2 meters before their lifeline pulls the rail.
If anyone has any ideas of how to calculate the required strength of the rail, your help would be appreciated.
(rail would be S355 steel and is allowed to deform but not break)
Google only gives me formulas where you have to 'assume' a certain amount of deflection to calculate the impact force, but that doesn't seem to be what I'm looking for.
I've tried using m.g.h=kx²/2 where:
k=48EI/L³
x=deflection of the rail
but kinda get stuck.
NX 7.5.5.4 with Teamcenter 8 on win7 64
Intel Xeon @3.2GHz
8GB RAM
Nvidia Quadro 2000