All,
I was hoping to have a discussion / direction on applying q=1.08 CFM delta T. I have a pump room that is 10' high, 13.3' wide and 14.8' long. Equipment is providing heat gain to the space of 52,480 Btu/hr and I am using a wall exhaust fan and intake louver. I have traditional designed around a 15 to 18 degree rise (use 18 for here). This calculates out to be about 2,700 CFM (81 ACH). This is about 20ft/s and the outside air is 99 deg. The equation tells me that I will be exhausting 117 degree air which I am having trouble (today) believing that air will actually heat up that much moving it through such a small space and that quickly. An air turn over rate of 15 seems more reasonable, but equation wise that is 500 CFM and a 97 degree wise.
The goal is to limit the temperature rise in the room. Is "q=1.08CFM delta T" being applied/interpreted correctly in this situation? Am I outside the limits of what that equation is meant to provide?
thanks
j
I was hoping to have a discussion / direction on applying q=1.08 CFM delta T. I have a pump room that is 10' high, 13.3' wide and 14.8' long. Equipment is providing heat gain to the space of 52,480 Btu/hr and I am using a wall exhaust fan and intake louver. I have traditional designed around a 15 to 18 degree rise (use 18 for here). This calculates out to be about 2,700 CFM (81 ACH). This is about 20ft/s and the outside air is 99 deg. The equation tells me that I will be exhausting 117 degree air which I am having trouble (today) believing that air will actually heat up that much moving it through such a small space and that quickly. An air turn over rate of 15 seems more reasonable, but equation wise that is 500 CFM and a 97 degree wise.
The goal is to limit the temperature rise in the room. Is "q=1.08CFM delta T" being applied/interpreted correctly in this situation? Am I outside the limits of what that equation is meant to provide?
thanks
j