Smackavelly
Mechanical
- Jan 14, 2009
- 9
If my NPSHR curve in the pump curve gives me a value of 10 ft (based on water). Do I need to correct it for a lower specific gravity (S.G) if my pumping liquid has a S.G. of .63. Do I simply do the following (see below)===>
NPSHR in the pump curve based on water (S.G.=1) is 10ft
h=P*2.31/S.G.
10ft=(P)*2.31/1
solve for P
P=10/2.31
Then convert that pressure to head (ft)using the process S.G.=.63
h=P*2.31/S.G.
h=(10/2.31)*2.31/.63= 10/.63=15.87ft
Would 15.87ft be considered NPSHR value of the pump in order to prevent cavitation when pumping the process having S.G=.63?
NPSHR in the pump curve based on water (S.G.=1) is 10ft
h=P*2.31/S.G.
10ft=(P)*2.31/1
solve for P
P=10/2.31
Then convert that pressure to head (ft)using the process S.G.=.63
h=P*2.31/S.G.
h=(10/2.31)*2.31/.63= 10/.63=15.87ft
Would 15.87ft be considered NPSHR value of the pump in order to prevent cavitation when pumping the process having S.G=.63?