Althalus
Structural
- Jan 21, 2003
- 151
I've never had this happen before. I'm wondering if anyone had this happen.
I've just done a hand calculation of the drainage before and after development.
Factors:
1) I used the rational method to determine Qp.
2)I started off with about 15% prairie and 85% Forest.
3)I have 15% impervious cover after development.
4) Runoff coefficients change with slope and soil type per our County manual.
Methods:
1) I've used McCuen's formula for sheet flow and the TR-55 formula for shallow concentrated flow (and the.
2) I used the formula for velocity found in Appendix F example for unpaved flow. (I determined that the longest Tc would be from the unpaved areas rather than the paved areas of the same shed).
3) I used that velocity to find the Tt for shallow concentrated flow (Eq 3-1).
Results:
1) Tc before (12.6min & 12.5min)
2) Tc After (17.1, 14.9, 13.5, 12.4 min)
3) Q(pre)= 38.9cfs
4) Q(post)= 39.6cfs
C went up, Area wend up. Somehow I didn't think Tc would have that big of an impact. But I had to shorten the flow length in the calculations to get the Q(post) to be higher than the Q(pre). The reason is that after development, the flow had to go through an intricate path of swales which increased the travel time. But I thought that the reviewer would never accept that if they saw it. So, I fudged the numbers to be more conservative.
Has anyone ever seen this before?
I've just done a hand calculation of the drainage before and after development.
Factors:
1) I used the rational method to determine Qp.
2)I started off with about 15% prairie and 85% Forest.
3)I have 15% impervious cover after development.
4) Runoff coefficients change with slope and soil type per our County manual.
The two pre-dev areas have different slopes than the four post-dev areas
The composite C(pre) = 0.28
The composite C(post) = 0.29
5) Total A(pre) = 7.73 acres; Total A(post) = 9.49 acres.Methods:
1) I've used McCuen's formula for sheet flow and the TR-55 formula for shallow concentrated flow (and the.
2) I used the formula for velocity found in Appendix F example for unpaved flow. (I determined that the longest Tc would be from the unpaved areas rather than the paved areas of the same shed).
3) I used that velocity to find the Tt for shallow concentrated flow (Eq 3-1).
Results:
1) Tc before (12.6min & 12.5min)
2) Tc After (17.1, 14.9, 13.5, 12.4 min)
3) Q(pre)= 38.9cfs
4) Q(post)= 39.6cfs
C went up, Area wend up. Somehow I didn't think Tc would have that big of an impact. But I had to shorten the flow length in the calculations to get the Q(post) to be higher than the Q(pre). The reason is that after development, the flow had to go through an intricate path of swales which increased the travel time. But I thought that the reviewer would never accept that if they saw it. So, I fudged the numbers to be more conservative.
Has anyone ever seen this before?