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Elastic section modulus (S) vs. plastic section modulus (Z)

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engr567

Structural
Aug 21, 2009
96
I am designing a freestanding steel handrail post (3'-6") spaced at 4'-0" on center maximumu. Per IBC, I am desiging this post for a point load of 200 lbs at the tip of free end. Per ASD design, can I use plastic section modulus (Z) in lieu of elastic section modulus (S)? The steel is 1" square solid ASTM A500 Grade B (Fy = 46 ksi). Thank you in advance for your input.
 
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FWIW, i'd use the plastic section for this "abuse" loading
 
If it is a welded base, I think the base connection will a problem with the 1" square. If it will be placed in grouted pocket, I agree with rb1957.

 
It is installed with grouted pocket. However, the question is - per AISC ASD design method - am I allowed to use plastic section modulus (Z)?
 
What edition of AISC ASD are you using? If you're using the 2005 specification, then yes.
 
Minor point of confusion, In europe Z is elastic modulus and S the plastic modulus.

Kieran
 
I don't think I agree with most of the above. You should use plastic section modulus for factored loads and elastic section modulus for unfactored loads, i.e. 200#.

BA
 
Yes it is AISC 13th ed. So, this is what I will do. Please correct if I am missing something here.

Mact = 200 * 3.5 = 700 lbs-ft. [at the base of the cantilever post)
Reqd. section modulus (S) = (700*12)/(1.67*46000) = x in3, where 1.67 = omega factor
Plastic section modulus (Z) = y in3
Since y is more than x, so the design is OK.
 
It depends on which AISC specification you are using.

ASD 9th Edition (Green manual)
Per section F2:
fb < Fb = 0.75 x Fy with stresses calculated per the elastic section modulus, S.

ASD 13th Edition (Black combined LRFD-ASD manual)
Per Section F11:
M(service) < [Mn = Mp = FyZ]/1.67
This uses the Plastic Section Modulus Z


 
engr567,

No, that is not right. The factor 1.67 should be in the numerator because allowable stress = 46,000/1.67 = 27,500 psi.

P = 200#
M = 200*3.5 = 700'#
S = 700*12/27,500 = 0.305 in^3

BA
 
Under the old ASD (in Canada) they permitted a greater fs to be used to accommodate the (0.75fy, I think) shape factor difference. For a solid square post, the shape factor Z/S is 1.5. We were the first class to use limit states, and I haven't used anything else since 1969...

I would typically use limit states (LRFD) and fy and Z, myself.

Dik
 
So would I, Dik.

Using LSD:

Pf = 200*1.5 = 300#
Mf = 300*3.5 = 1050'# = 12,600"#
Z req'd. = Mf/[&phi;]Fy = 12,600/(0.9*46000) = 0.304 in^3

This is almost the same result as I found for S earlier which suggests that elastic design is more conservative.

BA
 
Also, ASTM A500 is a tube steel specification. Square bars are not covered by this specification.
 
engr567,

Just be aware when reviewing BAretired's and dik's responses as they are referring to Canadian codes/specs - their responses are most likely correct as far as the Canada codes go but you did refer to the IBC which refers to AISC specifications which differ somewhat.
 
BAretired, you are correct. 1.67 should be in the numerator. Thanks.
FYI, this project is in US, and codes are IBC 2006 and AISC 13ed.
 
1x1 inch posts are a little smaller than what is usually installed. 1-1/2 x 1-1/2 look better, and are the usual posts, with 1x1 tube steel as the top and bottom of the rail.

Or a 1 inch channel, punched at 4 inch interval for the 1/2 square vertical rods. Punched channel is adequate and only sags "a little" after several years service, but it is not very artistic or pretty.
 
@BA:
Is the 1.5 multiplier an overload factor?
If it is considered a live load, the multiplier is 1.6. Right?

 
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