Apr 26, 2011 #1 jl87ma Mechanical Sep 20, 2010 9 Hi I was hoping someone could tell me where this equation was derived from, dP=2*A*pi*Hz where, dP= Change in pressure A: Amplitude Hz: Frequency
Hi I was hoping someone could tell me where this equation was derived from, dP=2*A*pi*Hz where, dP= Change in pressure A: Amplitude Hz: Frequency
Apr 26, 2011 Thread starter #2 jl87ma Mechanical Sep 20, 2010 9 the equation was taken from this context, http://hydraulicanswers.blogspot.com/2009/09/valliappan-said.html Upvote 0 Downvote
the equation was taken from this context, http://hydraulicanswers.blogspot.com/2009/09/valliappan-said.html
Apr 26, 2011 #3 hydtools Mechanical Apr 4, 2007 3,265 A is the peak pressure amplitute 2*pi*HZ = rotational velocity = omega pressure rate of change = dP/dt = A*omega = A*2*pi*Hz Imagine a disk of radius A spinning at rotational speed omega. The radius rate of change is A*omega. Ted Upvote 0 Downvote
A is the peak pressure amplitute 2*pi*HZ = rotational velocity = omega pressure rate of change = dP/dt = A*omega = A*2*pi*Hz Imagine a disk of radius A spinning at rotational speed omega. The radius rate of change is A*omega. Ted
Apr 26, 2011 Thread starter #4 jl87ma Mechanical Sep 20, 2010 9 Ted thank you. There is another potential question but I will think about it a little further before I ask. Thank you once again. Upvote 0 Downvote
Ted thank you. There is another potential question but I will think about it a little further before I ask. Thank you once again.
