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FLA vs power consumption vs motor hp

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mech4321

Mechanical
Jun 8, 2009
14
Hi,

We have to evaluate the power consumption at steady load of a fluid cooler which have at 600V an FLA of 23A. That would give approximately kw = 600 x 23 x 1.73 = 23.9 kw or 32 hp. However, the fluid cooler has only a total of motor of 6 x 1.5 hp = 9 hp (plus a small amount for the controls). Where does come this big differance? How can we evaluate the consumption if this value is not available from the manufacturer.

Thanks
Alex
 
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But there are only 6, not 9


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Hit the Send button too quick.

It also does not say 23kVA, it says "23 FLA". So even if you are at 3A per 1-1/2HP 600V motor, that is still not getting to 23A.

My point is simply that the numbers do not add up in my opinion, so somewhere, there is data in/on that cooling system that is inaccurate or open to gross misinterpretation.

"Dear future generations: Please accept our apologies. We were rolling drunk on petroleum."
— Kilgore Trout (via Kurt Vonnegut)

For the best use of Eng-Tips, please click here -> faq731-376
 
I think the quote sheet may list the wrong voltage.

Although for a slightly different product model number, the "-4B" specifies 460V motors with 115 volt controls. On that model the total watts is 8682 Watts (1447 W/Fan). The quote sheet also lists MCA/FLA/MOPD instead of FLA/MCA/MOPD. Would a power factor of 0.5 be reasonable. Assuming 0.5 pf gets you to the listed 21.6 FLA.
 
My bad on the number of motors, Jeff.
I was basing the KVA on this sentence from the first post.
"That would give approximately kw = 600 x 23 x 1.73 = 23.9 kw or 32 hp."
But I pretty much agree with you.
Time for us to stop guessing.

Bill
--------------------
"Why not the best?"
Jimmy Carter
 
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