Flat Out Pattern for Eccentric Reducer Calculation 1

[fglass]

Does anybody know the way to determine flat out pattern of an eccentric reducer? Assuming that the small OD is 5" and big OD is 12". Thanks

 

[RWF7437]

Wouldn't the flat out pattern be a trapezoid with one base = 5" x Pi and the other base = 12" x Pi and a length ( height ) = whatever the length of the desired reducer ? The "bases" would be parallel but not "concentric" ? Can't you make one out of paper to see if this makes sense ?

good luck

 

[fglass]

RWF7437,

No, you way does not work out right. Yes, the base is parallel.

 

[RWF7437]

fglass,

Your answer is ambiguous. If my way did not work out right, were you able to solve the problem by building a simple paper model ? Seems like you should be able to.

good luck

 

[fglass]

Oh, I mean does anybody know the formula to determine the flat out pattern of an eccentric reducer by knowing the small OD, big OD and the height of a reducer? Building the paper model is tedious as we have many different sizes of eccentric reducers.

I know the way to calculate the flat out pattern of a CONCENTRIC reducer, but not for ECCENTRIC reducer.

 

[RWF7437]

http://www.tpub.com/content/draftsman/14040/css/14040_138.htm

 

[BigInch]

That doesn't look like a reducer.

http://virtualpipeline.spaces.msn.com

 

[PeterCharles]

Personally, I'd download the free version of SketchUp (which is a surface modeller), create the reducer, use the un-fold plug-in to create a flat pattern and export this as a DXF.

 

[MikeHalloran]

You have to truncate the oblique cone to make an eccentric reducer.

The page presents a visual outline of the technique, which is probably not real clear if you haven't ever done it.




Mike Halloran
Pembroke Pines, FL, USA