SliceCity
Structural
- Dec 22, 2022
- 16
Hello All,
I am working on the design of a second story addition for a residential house. I am trying to carry the second story shear wall load in the first story diaphragm and shear walls. Due to the existing condition constraint, I cannot place a shear wall directly under the second story shear wall to transfer the load. I currently have the second story shear wall supported by a beam with collectors. I am hoping for a sanity check to confirm that I am analyzing this correctly.
I am assuming that 40% of the second story shear wall will transfer through the diaphragm be resisted by the north face shear walls. The remaining 60% of the second story shear walls will be supported by the two west faced shear walls at the living area and the nook. Since I have discontinuity between the two west faced shear wall, due to the opening above, I am thinking that the way I distributed the loads is not correct. I am thinking that along the length where I have a discontinuous diaphragm, all the load will transfer to the north face shear wall. I would divide the shear load by the total length (say 50ft) 4500/50= 90lb/ft then assuming the length of the discontinuous diagram is about 16.5ft i would apply 1500ft along the north shear walls + 40% of the remaining load. I would then apply 60% of the remaining load along the south face shear walls.
Please see attached.
I am working on the design of a second story addition for a residential house. I am trying to carry the second story shear wall load in the first story diaphragm and shear walls. Due to the existing condition constraint, I cannot place a shear wall directly under the second story shear wall to transfer the load. I currently have the second story shear wall supported by a beam with collectors. I am hoping for a sanity check to confirm that I am analyzing this correctly.
I am assuming that 40% of the second story shear wall will transfer through the diaphragm be resisted by the north face shear walls. The remaining 60% of the second story shear walls will be supported by the two west faced shear walls at the living area and the nook. Since I have discontinuity between the two west faced shear wall, due to the opening above, I am thinking that the way I distributed the loads is not correct. I am thinking that along the length where I have a discontinuous diaphragm, all the load will transfer to the north face shear wall. I would divide the shear load by the total length (say 50ft) 4500/50= 90lb/ft then assuming the length of the discontinuous diagram is about 16.5ft i would apply 1500ft along the north shear walls + 40% of the remaining load. I would then apply 60% of the remaining load along the south face shear walls.
Please see attached.