Hi israelkk:
Thanks for ur reply. I did calculate using the following the formulae.But I am getting huge stress on worm gear tooth & huge Tangential force on gear (2174.lbf)which I sould'nt expect because the gear I selected is rated for .23 HP and 1550 lbf*in output torque.In my case power is only .03 hp & output torque is 600 lbf*in(this gear has to lift weight of 200.lbf, worm wheel is connected to pulley (dia=6in, hence torque=600 lbf*in).
Please can any one check these calculation for me & tell why Tangential force on worm is so less & Tangential force on gear is so high& also stress on the worm gear tooth is so high when rated capacity for the chosen gear are high.
T1=255lbf*in, d1=2*in (dia of worm), ? n=14.5 deg, ?=4.4, ?=.04 gear ratio=20:1
d2=3.3*in (dia of worm gear), diametrical pitch=6
Tangential force on worm ( F wt )= axial force on wormwheel
F wt = F ga = 2.T 1 / d 1
F wt=255.lbf(my answer)
Axial force on worm ( F wa ) = Tangential force on gear
F wa = F gt = F wt.[ (cos ? n - ? tan ? ) / (cos ? n . tan ? + ? ) ]
F gt=2174.lbf(my answer)
Modified Lewis equation for stress induced in worm gear teeth
? a = F wt / ( p x. b a. y )(N)
b a=1*in(face width) y=0.1
F wt = Worm gear tangential Force (N)
module m=d2/20=.164*in
Axial circuler pitch px=3.142*m=.51*in