ONENGINEER
Geotechnical
- Oct 13, 2011
- 284
Hi
I understand well the concept and application of FoS. However, having gone through the Canadian Foundation Manual, I have a difficulty to understand the geotechnical resistance factor. For example, a resistance factor of 0.5 is recommended for vertical bearing resistance of shallow foundations in CFEM. This means (0.5) x R, where R is the geotechnical ultimate resistance predicted from theoretical analysis using unfactored geotechnical parameters. Isn't that similar to dividing the calculated foundation bearing capacity by a FoS of (2). I.e., R x 0.5 (per CFEM) = R / (2) (per e.g. Navfac)
I am sure there is more into it but looking at some examples of design calculations by engineers, it seems the same outcome is expressed with two types of vocabularies one of them being more trendy. Could someone familiar with CFEM enlighten me. For example, what does one gain by using CFEM instead of traditional allowable load calculations. Thank you.
I understand well the concept and application of FoS. However, having gone through the Canadian Foundation Manual, I have a difficulty to understand the geotechnical resistance factor. For example, a resistance factor of 0.5 is recommended for vertical bearing resistance of shallow foundations in CFEM. This means (0.5) x R, where R is the geotechnical ultimate resistance predicted from theoretical analysis using unfactored geotechnical parameters. Isn't that similar to dividing the calculated foundation bearing capacity by a FoS of (2). I.e., R x 0.5 (per CFEM) = R / (2) (per e.g. Navfac)
I am sure there is more into it but looking at some examples of design calculations by engineers, it seems the same outcome is expressed with two types of vocabularies one of them being more trendy. Could someone familiar with CFEM enlighten me. For example, what does one gain by using CFEM instead of traditional allowable load calculations. Thank you.