ReverseEntropy
Mechanical
- Jul 28, 2008
- 8
This question relates to drag coefficients and the drag force. This should be very easy, but I cannot find a reference that gives the formula for Frontal Area (Fa) for a square cylinder (i.e., a box). On one hand, it should be as simple as Length * Height of the windward face (where the length is oriented horizontally).
However, often the drag coefficient is shown with a little picture of a box with the length oriented horizontal. They call out the Length and Depth as if L*D should give the value for Fa. But, wouldn't L*H instinctively make more sense? (In this case, height would be the width of the windward face.)
In my case, I have a box standing vertically (i.e., with the length oriented vertically) wouldn't Fa = Height * Width? (Some people I've asked were taught Fa is also called the projected area, but I can't find a reference to confirm that, either!)
Whatever the formula, I need a reference - preferably a fluids text I should be able to find at a college library.
Thanks!
However, often the drag coefficient is shown with a little picture of a box with the length oriented horizontal. They call out the Length and Depth as if L*D should give the value for Fa. But, wouldn't L*H instinctively make more sense? (In this case, height would be the width of the windward face.)
In my case, I have a box standing vertically (i.e., with the length oriented vertically) wouldn't Fa = Height * Width? (Some people I've asked were taught Fa is also called the projected area, but I can't find a reference to confirm that, either!)
Whatever the formula, I need a reference - preferably a fluids text I should be able to find at a college library.
Thanks!