Hi,
This is not a theoretical question
I and designing a heat exchanger.
I am planing to use copper as the material that will exchange the hit.
I'm having trouble deciding about the area of the heat transfer.
I am familiar with a heat exchanger, for the same application, that exchange heat using iron that gets the job done. This heat exchanger area is 0.6 m^2.
Iron thermal conductivity coefficient is about 85 W/m K (correct me if I am mistaken).
Copper thermal conductivity coefficient is about 400 W/m K (again correct me as needed).
Is that mean that I can use about 4 times less area to do the same heat transfer?
I believe that is what the math says, but it doesn't sound like it would work in real world.
Should I somehow take into consideration the materials that transfer and collects the heat?
Would be happy to hear your thoughts.
Thanks,
Ron
This is not a theoretical question
I and designing a heat exchanger.
I am planing to use copper as the material that will exchange the hit.
I'm having trouble deciding about the area of the heat transfer.
I am familiar with a heat exchanger, for the same application, that exchange heat using iron that gets the job done. This heat exchanger area is 0.6 m^2.
Iron thermal conductivity coefficient is about 85 W/m K (correct me if I am mistaken).
Copper thermal conductivity coefficient is about 400 W/m K (again correct me as needed).
Is that mean that I can use about 4 times less area to do the same heat transfer?
I believe that is what the math says, but it doesn't sound like it would work in real world.
Should I somehow take into consideration the materials that transfer and collects the heat?
Would be happy to hear your thoughts.
Thanks,
Ron