zenapp
Chemical
- Nov 24, 2011
- 6
Hi, Im hoping someone can help me out,
Id like to understand the rules around flow in a heat exchanger and how they link to heat transfer. I have a CHP engine generating electricity and heat is recovered from a water cooling system on board through plate heat exchanger where it heat process water for a plant.
The equation im using to calculate heat transfer is -
Dh = C_p *M * dT
where
Dh = Change in heat (energy)
C_p = heat capacity
M = Mass (volume in heat ex)
dT = Change in temperature
On the engine side water is in the exchanger, inlet temperature is 90C, outlet temperature is 80C flow rate is 40m3/h
On the process side of the exchanger it is also water, inlet temperature is 61C, outlet temp is 68C flow rate is also 40m3/hr
Energy Removed from engine side circuit - 4.18kj/kg * 40,000 * 10 = 1672000kJ (464kW equiv)
Energy taken on into process side circuit - 4.18kj/kg * 40,000 * 7 = 1117200kJ (310kW equiv)
My calculations show in an excel model that increasing the flow rate increases heat recovered, although I can manipulate the flow to achieve impossible results, such as increasing the engine flow to 60m3/hr would mean (in the model) 696kW heat taken from the engine, I know this isnt possible from the engine data sheet, in the same way the process side recovers more heat than removed from the engine circuit if I double the flow so that not possible either.
I have attached a model that shows what im working with.
When it comes to optimising or designing flow rate is there a set of rules to use to help. Any help with this appreciated.
Thanks Zen
Id like to understand the rules around flow in a heat exchanger and how they link to heat transfer. I have a CHP engine generating electricity and heat is recovered from a water cooling system on board through plate heat exchanger where it heat process water for a plant.
The equation im using to calculate heat transfer is -
Dh = C_p *M * dT
where
Dh = Change in heat (energy)
C_p = heat capacity
M = Mass (volume in heat ex)
dT = Change in temperature
On the engine side water is in the exchanger, inlet temperature is 90C, outlet temperature is 80C flow rate is 40m3/h
On the process side of the exchanger it is also water, inlet temperature is 61C, outlet temp is 68C flow rate is also 40m3/hr
Energy Removed from engine side circuit - 4.18kj/kg * 40,000 * 10 = 1672000kJ (464kW equiv)
Energy taken on into process side circuit - 4.18kj/kg * 40,000 * 7 = 1117200kJ (310kW equiv)
My calculations show in an excel model that increasing the flow rate increases heat recovered, although I can manipulate the flow to achieve impossible results, such as increasing the engine flow to 60m3/hr would mean (in the model) 696kW heat taken from the engine, I know this isnt possible from the engine data sheet, in the same way the process side recovers more heat than removed from the engine circuit if I double the flow so that not possible either.
I have attached a model that shows what im working with.
When it comes to optimising or designing flow rate is there a set of rules to use to help. Any help with this appreciated.
Thanks Zen