Hi All I need help in the calcul

[neps3]

Hi All

I need help in the calculation of dielectric loss (W/cm3) when subjected to a 50Hz AC supply. ie 4kV/mm. Assume a tan delta value.

Thanks in advance

 

[mersin33]

kantor,

tan delta is a measurement of imperfection of a dielectric medium (ratio of watt losses-imperfection- to var reading-perfect dielectric represented by a capacitor)

just like calculating VAR, W and VA from power triangle, use tangent of angle delta. Assume VAR producing capacitor is parallel with W producing resistor. (in order to find these 3 values, you need to have another reading with tan delta value, VAR value maybe).

divide the calculated total W loss by the volume of the dielectric (assuming uniformity)

hope this helps

 

[neps3]

saltan

Are you familier with any formula for the loss calculation.

Thanks

 

[jbartos]

Suggestion: Since the original posting is very general, the following links can apply:

http://www.qsl.net/wb6tpu/si-list/att-0017/01-I-k.PDF

http://canopus.physik.uni-potsdam.de/~s_bange/programs/Perl/kktrans/poster/POSTERA4.PS

(postcrip file)

http://www.cst.de/company/news/press/MWJournal_Aug_2002.pdf

http://www.emf.eei.uni-erlangen.de/Aktuelles/Fischer/pdf/EMC_2003.pdf

etc. for more info

 

[pratikoze]

Kantor,
To calculate di-electric loss one has to use formula
dielectric loss in watts = 2*3.142*f*c*v*v*tan delta

 

[neps3]

Thanks All and JB thanks to you.