TempEng01
Structural
- Oct 3, 2019
- 1
Hi there, I am a graduate engineer so any help on this would be great as the senior engineers at my work are also puzzled with this one!
We are doing a backpropping design for this hoist and coming up with some ridiculous cumulative loads that need to get backpropped for a 3kpa total slab kPa (2LL & 1DL).
There is a 38kN compression load per hoist leg per level for the 4no. mandatory slab levels.
Working with a shoe size of 800mm and overall hoist width of 5m I have taken a (non-conservative) tributary area of 2.25m[sup]2[/sup] (1.5m X 1.5m).
2.25m[sup]2[/sup] x 3kPa = 6.75kN usable slab capacity
My resulting calculations per leg are as follows:
level 4 38 - 6.75 = 31.25kN
level 3 31.25+38-6.75 = 62.5kN
level 2 62.5+38-6.75 = 93.75kN
level 1 93.75+38-6.75 = 125kN final load to be backpropped
Now my peers and I have done plenty of backpropping designs before and never come across loads like the above. Is there anything I am doing wrong or missing?
Any help would be much appreciated, thank you in advance
We are doing a backpropping design for this hoist and coming up with some ridiculous cumulative loads that need to get backpropped for a 3kpa total slab kPa (2LL & 1DL).
There is a 38kN compression load per hoist leg per level for the 4no. mandatory slab levels.
Working with a shoe size of 800mm and overall hoist width of 5m I have taken a (non-conservative) tributary area of 2.25m[sup]2[/sup] (1.5m X 1.5m).
2.25m[sup]2[/sup] x 3kPa = 6.75kN usable slab capacity
My resulting calculations per leg are as follows:
level 4 38 - 6.75 = 31.25kN
level 3 31.25+38-6.75 = 62.5kN
level 2 62.5+38-6.75 = 93.75kN
level 1 93.75+38-6.75 = 125kN final load to be backpropped
Now my peers and I have done plenty of backpropping designs before and never come across loads like the above. Is there anything I am doing wrong or missing?
Any help would be much appreciated, thank you in advance