How can I calculate the axial load F1, F2, when having eccentrical loading.

[takio]

Hello

Can anyone please help me with this?
The shaft is located through the two holes on the rectangular hollowed structure.
When applying the load P,
How can I calculate the force 1 and 2?

Thank you

 

[desertfox]

Hi takio

I would take moments about where F1 acts so :- P*a = F2*2b
Transpose and find F2. Then F1= P-F2


“Do not worry about your problems with mathematics, I assure you mine are far greater.” Albert Einstein

 

[Scuka]

As always - free body diagram, equilibrium equations.

 

[Tmoose]

I would not have described F1 and F2 as "axial" loading.

 

[takio]

Thank you Deserfox.
So did you consider F1 location as pivot?

Would you please help me with this once again?
What would happen if there are two hollowed structure with one shaft?
Would that be..
-P*a=F2*2B=F3*(2B+C)=F4*(4B+C)

 

[desertfox]

Hi takio

Yes, in your original post I took F1 as a pivot point.

In your latest post the structure is statically indeterminate, that means it can’t be solved as easy like your first post. You need way more information than you have posted so far.

“Do not worry about your problems with mathematics, I assure you mine are far greater.” Albert Einstein

 

[Tmoose]

"So did you consider F1 location as pivot?"

Either F point could have been used.

"sum of moments"

 

[dik]

Another way of looking at this... with the left side P gone (forgot to delete it). fixt...

So strange to see the singularity approaching while the entire planet is rapidly turning into a hellscape. -John Coates

-Dik