How much Load will swing 1

[dgkhan]

Load is hanged from a crane by a cable. Crane suddenly stops, hence,
load and cable behave as Pendulum. If I know length of cable and weight
of load, by what equation I can find how much further the load will swing?

 

[dgkhan]

I also know speed of crane

 

[csd72]

You need to use conservation of energy.

Kineteic energy at crane stop = potential energy at top of swing. Look up your physics texts for this type of situation.

csd

 

[msquared48]

Answer #2: If the crane operator is good, and here I mean more than competent, when the crane stops, the load will not
swing at all.

Mike McCann
McCann Engineering

 

[Denial]

CSD72's approach will work it all cases of a sudden stop following a "steady state" horizontal movement.

If the weight's post-stop pendulum motion is going to be small enough, your problem can be treated as standard simple harmonic motion:
displacement = x = a*sin(wt)
and
velocity = x' = aw*cos(wt)

For a pendulum with small displacements, w = sqrt(g/L).
At the time the crane stops moving, t=0 and
x' = crane's previous travel velocity.
Hence solve the velocity equation for "a", which is the answer you seek.