how to calculate the foundation for a 2 MW generator 2

[181273]

I´m trying to define the foundation for a 2 MW syncronous generator, and I don´t know how to calculate the next things maybe someone of you could help me....
How can I calculate the short circuit torque and how to use it for the calculation of the foundation... this is a horizontal hydro unit with francis runner....
What is the best option: double T asembly or a piece of metal mechanized with the holes for the bolts of the generator??
sorry for my badly english and I hope to get some help from you... I´m just trying to know how to know how to do it

thanks in advance

 

[motorspert]

Davidbeach,
Torque is only really power for a continuous period. During the very short time of a short circuit the stored magnetic energy disipates in any way it can generates high currents in the stator. These currents create magnetic fields which cause the rotor to accelerate or decelarate which is seen as an accelerating torque. These torques occur for a very short time so there is no useful power produced.

Regards

 

[davidbeach]

Then you are defining torque as something other than Power over angular velocity.

Prior to the fault the mechanical torque in is equal to the electrical power out divided by the angular velocity plus losses. Immediately after the fault the mechanical torque is unchanged, the electrical power out has fallen drastically, and the losses remain unchanged. In the short time following the fault, the mechanical power remains unchanged, the electrical power remains at the lower level and the power imbalance causes the shaft to accelerate. As the shaft accelerates the angular velocity goes up, therefore the mechanical torque in goes down. No increase in torque following a fault so long as torque is defined as power divided by angular velocity.