how to create my own imposed displacement field 1

[bobof77]

I'd like to apply my own created imposed dislacement
to a set of nodes. What is the best way to do it?

 

[Drej]

D, NODE, Lab, VALUE, VALUE2, NEND, NINC, Lab2, Lab3, Lab4, Lab5, Lab6

Defines DOF constraints at nodes.

 

[bobof77]

I know this command,
but it is not convinient!

Is it possible to treat a set of nodes
at the same time? Or to apply a local rotation
(on elements SOLID45)! Anyway, the element SOLID45 has
only UX UY UZ as DOF.

 

[Drej]

Put the nodes you want into a component, then reference this component in the D command.

 

[bobof77]

But the imposed displacement that I want is not a
uniform one

 

[Drej]

Rather than giving fragments of poor information, why don't you explain your problem clearly and in proper detail.

 

[JaStKn]

You have worked with arrays before?

For example you have 10 nodes. (node numbers are: 11,16,27,101 ...).

You can define a vector with the *dim comand.

*dim,name,array,10,2

and fill the vector with node numbers and contraints.

may be:

name(1,1)=11
name(1,2)=0.1
name(2,1)=16
name(2,2)=0.2
....

or with vector operations:
(*vfil, *voper, *vfun, *mfun ...)

If you have the vector, you can define the constraints with a do loop:

*do,i,1,10
d,name(i,1),ux,name(i,2)
*enddo

Or with an implied do loop:

d,name(1:10,1),ux,name(1:10,2) -> works faster by big problems!