Hydraulic Jack Spacer or Extension

[BuonGiorno]

I have a hydraulic jack with an 8 inch diameter piston. This means the surface area of piston head is about 50.25 sq. Inches. If I apply 10,000 psi with a hydraulic pump then the force that this jack can lift is about 251.2 Tons.

F= P*A
251.2 = 10,000 psi * 50.25

I understand that this holds true because of Pacal's law of incompressible liquids.

However, what is the effect if I add a solid metal round spacer or extension of any given diameter between the jack head and the load? How can I calculate this effect?

Thanks...

 

[EdStainless]

If you change the size of the contact it will change the pressure at the contact surface but not the force.

 

[LittleInch]

Not sure this has anything really to do with Pacals Law.

If by "jack head" you mean the external part of the hydraulic cylinder then Eds answer is correct.

If you mean something else then please sketch it so we can understand what you're asking.