2brains
Mechanical
- Apr 30, 2011
- 11
I am building lathe to peel pieces of veneer approx 0.160" off of pieces of logs. I sliced pieces off with an arbor press and with some tweaking was very pleased with the results. I have decided that the max torque needed would be 6000inlb. A 3/4hp motor came with the wood lathe. Until I thought of this I was going to buy a 60:1 gear reducer ($272.) and 4 sprockets, 2 chains, and another intermediate shaft with pillow block bearings etc. and reduce the rpm to almost 6 rpm. Then I found I could buy a hydraulic pump with 0.065cu in disp and a hydraulic motor with 5cu in disp and combined with another 2:1 reduction with chain and sprockets have a much simpler setup with a lot more freedom to place the motor etc and get a similar final rpm. The hydraulic approach should cost me a little more, but be much easier and straightforward to put together. The motor should produce at the shaft almost 25inlb and as as I said the final torque could reach 6000inlb. I majored in math and only took a few engineering courses and took fluid mechanics, but we didn't discuss anything like this. After some reasoning here I concluded all I need to do is compare the displacement of the pump to the motor to determine input, output torque. Electric motor rpm is 1800. Am I correct and do you think this will work? If my original experiment wasn't easy I wouldn't be doing it nor would others find it practical.