simar187
Mechanical
- Dec 30, 2007
- 19
I am using Cosmos Floworks to model and measure the hydrostatic torque that the flow of air would have on the disk of a butterfly damper.
The mass flow rate of air at the inlet is 15.3125 lbs/s, the pressure is approximately 14.477 psi. Since the system has a pressure drop of 0.725 psi, I am setting the pressure at the outlet to equal 13.752 psi. The CFD measures the vertical (x-axis; down is +) and horizontal (z-axis; back is +) forces on the back face of the disk (the flow is coming from the shaft side), as well as the torques in the y-axis. Using the pressures identified above, with the disc open to an angle of 80 degrees, the CFD returns the following data:
SG X - Component of Normal Force 1 [lbf] 343.5396509
SG Z - Component of Normal Force 1 [lbf] 61.96892146
SG X - Component of Force 1 [lbf] 343.545461
SG Z - Component of Force 1 [lbf] 61.92268904
SG Y - Component of Torque 1 [lbf*in] 911.5025292
SG Av Static Pressure 1 [lbf/in^2] 13.76498049
SG Av Static Pressure 2 [lbf/in^2] 13.752
Pressure Drop [lbf/in^2] 0.012980487
However, if I change the outlet pressure to atmosphere, and the approximate temperature at my mass flow rate to 1atm+0.725psi, the CFD generates the following data:
SG X - Component of Normal Force 1 [lbf] -3.283694062
SG Z - Component of Normal Force 1 [lbf] -0.86486757
SG X - Component of Force 1 [lbf] -3.278246323
SG Z - Component of Force 1 [lbf] -0.908334988
SG Y - Component of Torque 1 [lbf*in] -31.90967134
SG Av Static Pressure 1 [lbf/in^2] 14.70810313
SG Av Static Pressure 2 [lbf/in^2] 14.6959473
Pressure Drop [lbf/in^2] 0.012155828
Its apparent that the forces and torque are changing significantly, despite the 0.752 psi pressure differential.
Any insights on how to explain this phenomena would be greatly appreciated.
Thanks, Simarjit Chouhan
The mass flow rate of air at the inlet is 15.3125 lbs/s, the pressure is approximately 14.477 psi. Since the system has a pressure drop of 0.725 psi, I am setting the pressure at the outlet to equal 13.752 psi. The CFD measures the vertical (x-axis; down is +) and horizontal (z-axis; back is +) forces on the back face of the disk (the flow is coming from the shaft side), as well as the torques in the y-axis. Using the pressures identified above, with the disc open to an angle of 80 degrees, the CFD returns the following data:
SG X - Component of Normal Force 1 [lbf] 343.5396509
SG Z - Component of Normal Force 1 [lbf] 61.96892146
SG X - Component of Force 1 [lbf] 343.545461
SG Z - Component of Force 1 [lbf] 61.92268904
SG Y - Component of Torque 1 [lbf*in] 911.5025292
SG Av Static Pressure 1 [lbf/in^2] 13.76498049
SG Av Static Pressure 2 [lbf/in^2] 13.752
Pressure Drop [lbf/in^2] 0.012980487
However, if I change the outlet pressure to atmosphere, and the approximate temperature at my mass flow rate to 1atm+0.725psi, the CFD generates the following data:
SG X - Component of Normal Force 1 [lbf] -3.283694062
SG Z - Component of Normal Force 1 [lbf] -0.86486757
SG X - Component of Force 1 [lbf] -3.278246323
SG Z - Component of Force 1 [lbf] -0.908334988
SG Y - Component of Torque 1 [lbf*in] -31.90967134
SG Av Static Pressure 1 [lbf/in^2] 14.70810313
SG Av Static Pressure 2 [lbf/in^2] 14.6959473
Pressure Drop [lbf/in^2] 0.012155828
Its apparent that the forces and torque are changing significantly, despite the 0.752 psi pressure differential.
Any insights on how to explain this phenomena would be greatly appreciated.
Thanks, Simarjit Chouhan