SamGabO
Civil/Environmental
- Sep 4, 2017
- 13
Does this sentence mean that whenever the load H resists the primary variable load effect, its load factor "H" shall be changed to 0.9 where the value of H is permanent? And throughout all other equations within this load combination, will the value of H be set to 0?
According to the exception on IBC 2015 1605.2 Load Combinations Using Strength Design or Load and Resistance Factor Design #2 "Where the effect of H resists the primary variable load effect, a load factor of 0.9 shall be included with H where H is permanent and H shall be set to zero for all other conditions."
For instance, in a tank, you have load combinations such as:
1.4(D +F)(Equation 16-1)
1.2 (D + F) + 1.6(L + H) + 0.5 (Lr or S or R)( Equation 16-2)
1.2(D + F) + 1.6 (Lr or S or R) + 1.6H + (f1L or 0.5 W)(Equation 16-3)
1.2(D + F) + 1.0W + f1L + 1.6H + 0.5 (Lr or S or R) (Equation 16-4)
1.2 (D + F) + 1.0E + f1L + 1.6H + f2S ( Equation 16-5)
0.9D+ 1.0W+ 1.6H(Equation 16-6)
0.9(D + F) + 1.0E+ 1.6H (Equation 16-7)
And given that the pressure of the fluid (F) inside the tank is being resisted by the lateral pressure (H) acting outside the tank. Will the primary load H be set to 0.9H and all other combinations including H be turned to 0 and would the load combinations then be like these?
1.4(D +F)(Equation 16-1)
1.2 (D + F) + 1.6(L) + 0.5 (Lr or S or R)( Equation 16-2)
1.2(D + F) + 1.6 (Lr or S or R) + (f1L or 0.5 W)(Equation 16-3)
1.2(D + F) + 1.0W + f1L + 0.5 (Lr or S or R) (Equation 16-4)
1.2 (D + F) + 1.0E + f1L + f2S ( Equation 16-5)
0.9D+ 1.0W (Equation 16-6)
0.9(D + F) + 1.0E (Equation 16-7)
Thank you in advance for your thoughts with regards to this matter.
According to the exception on IBC 2015 1605.2 Load Combinations Using Strength Design or Load and Resistance Factor Design #2 "Where the effect of H resists the primary variable load effect, a load factor of 0.9 shall be included with H where H is permanent and H shall be set to zero for all other conditions."
For instance, in a tank, you have load combinations such as:
1.4(D +F)(Equation 16-1)
1.2 (D + F) + 1.6(L + H) + 0.5 (Lr or S or R)( Equation 16-2)
1.2(D + F) + 1.6 (Lr or S or R) + 1.6H + (f1L or 0.5 W)(Equation 16-3)
1.2(D + F) + 1.0W + f1L + 1.6H + 0.5 (Lr or S or R) (Equation 16-4)
1.2 (D + F) + 1.0E + f1L + 1.6H + f2S ( Equation 16-5)
0.9D+ 1.0W+ 1.6H(Equation 16-6)
0.9(D + F) + 1.0E+ 1.6H (Equation 16-7)
And given that the pressure of the fluid (F) inside the tank is being resisted by the lateral pressure (H) acting outside the tank. Will the primary load H be set to 0.9H and all other combinations including H be turned to 0 and would the load combinations then be like these?
1.4(D +F)(Equation 16-1)
1.2 (D + F) + 1.6(L) + 0.5 (Lr or S or R)( Equation 16-2)
1.2(D + F) + 1.6 (Lr or S or R) + (f1L or 0.5 W)(Equation 16-3)
1.2(D + F) + 1.0W + f1L + 0.5 (Lr or S or R) (Equation 16-4)
1.2 (D + F) + 1.0E + f1L + f2S ( Equation 16-5)
0.9D+ 1.0W (Equation 16-6)
0.9(D + F) + 1.0E (Equation 16-7)
Thank you in advance for your thoughts with regards to this matter.