marty007
Mechanical
- Mar 8, 2012
- 622
Hey everyone,
I was reviewing some in-service inspection t-min values for an ASME VIII-1 vessel. Currently we are setting the initial t-min value for piping nozzles as t-nom - CA. For a 12"-sch.120 piping nozzle with 1/8" CA for example, this would be 1" - 0.125" = 0.875". When the nozzle neck nears 0.875" during inspections either the nozzle is repaired, replaced, or a more detailed FFS analysis is performed.
What this doesn't consider however is the 12.5% under tolerance on piping components. Per code, this nozzle could have a maximum under tolerance of 1" x 12.5% = 0.125", meaning the wall thickness could already be 0.875" in the new condition. This would be flagged immediately during the very first inspection for repair/replacement, which doesn't make sense.
Would it be appropriate instead to set the initial t-min value for nozzles fabricated from piping components to: (t-nom * 87.5%) - CA? In the case of the example provided, this would set the initial t-min to: (1" * 87.5%) - 0.125" = 0.75".
Thanks!
Marty
I was reviewing some in-service inspection t-min values for an ASME VIII-1 vessel. Currently we are setting the initial t-min value for piping nozzles as t-nom - CA. For a 12"-sch.120 piping nozzle with 1/8" CA for example, this would be 1" - 0.125" = 0.875". When the nozzle neck nears 0.875" during inspections either the nozzle is repaired, replaced, or a more detailed FFS analysis is performed.
What this doesn't consider however is the 12.5% under tolerance on piping components. Per code, this nozzle could have a maximum under tolerance of 1" x 12.5% = 0.125", meaning the wall thickness could already be 0.875" in the new condition. This would be flagged immediately during the very first inspection for repair/replacement, which doesn't make sense.
Would it be appropriate instead to set the initial t-min value for nozzles fabricated from piping components to: (t-nom * 87.5%) - CA? In the case of the example provided, this would set the initial t-min to: (1" * 87.5%) - 0.125" = 0.75".
Thanks!
Marty