JustSomeRoark
Chemical
- Apr 12, 2007
- 18
Dear all,
When compressor Vendors state the moment of inertia of their machines/drivers they normally state the MOI and a reference speed. I have never fully understood why: I assumed that the moment of inertia of a rotating element is constant irrespective of its speed.
Aspentech HYSYS' manual for dynamic simulation states the following:
"If you have inertia for different parts of the train rotating at different speeds, you need to pro-rate these to a common speed basis using the formula
Ib = SUM(Ii * GRi^2)
where:
Ib = rotational inertia with respect to some base speed
Ii = rotational inertia of the ith component on the rotating shaft (with respect to the speed at this gear ratio)
GRi = gear ratio of the ith component defined at wi/wb (angular speed of ith component divided by base angular speed)"
Therefore, if the compressor has a MOI of 2 kgm2 @ 18000 rpm but I want to express its MOI at 1800 rpm then the following calculation is required:
MOI@1800rpm = MOI@18000rpm * (18000/1800)^2 = 2 * (10)^2 = 200 kgm2 @ 1800 rpm
Does this make sense to you? Why is the MOI dependent of a certain "reference speed"?
Regards.
When compressor Vendors state the moment of inertia of their machines/drivers they normally state the MOI and a reference speed. I have never fully understood why: I assumed that the moment of inertia of a rotating element is constant irrespective of its speed.
Aspentech HYSYS' manual for dynamic simulation states the following:
"If you have inertia for different parts of the train rotating at different speeds, you need to pro-rate these to a common speed basis using the formula
Ib = SUM(Ii * GRi^2)
where:
Ib = rotational inertia with respect to some base speed
Ii = rotational inertia of the ith component on the rotating shaft (with respect to the speed at this gear ratio)
GRi = gear ratio of the ith component defined at wi/wb (angular speed of ith component divided by base angular speed)"
Therefore, if the compressor has a MOI of 2 kgm2 @ 18000 rpm but I want to express its MOI at 1800 rpm then the following calculation is required:
MOI@1800rpm = MOI@18000rpm * (18000/1800)^2 = 2 * (10)^2 = 200 kgm2 @ 1800 rpm
Does this make sense to you? Why is the MOI dependent of a certain "reference speed"?
Regards.